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20304153553 = 96493210421
BaseRepresentation
bin10010111010001110…
…001100101111010001
31221102000211212111011
4102322032030233101
5313040330403203
613154432250521
71316104312645
oct227216145721
957360755434
1020304153553
11867a1900a2
123b279a0a41
131bb76cb158
14da885ac25
157dc7ea76d
hex4ba38cbd1

20304153553 has 4 divisors (see below), whose sum is σ = 20304460468. Its totient is φ = 20303846640.

The previous prime is 20304153491. The next prime is 20304153557. The reversal of 20304153553 is 35535140302.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10141094209 + 10163059344 = 100703^2 + 100812^2 .

It is a cyclic number.

It is not a de Polignac number, because 20304153553 - 217 = 20304022481 is a prime.

It is a super-3 number, since 3×203041535533 (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20304153557) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8718 + ... + 201703.

It is an arithmetic number, because the mean of its divisors is an integer number (5076115117).

Almost surely, 220304153553 is an apocalyptic number.

It is an amenable number.

20304153553 is a deficient number, since it is larger than the sum of its proper divisors (306915).

20304153553 is an equidigital number, since it uses as much as digits as its factorization.

20304153553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 306914.

The product of its (nonzero) digits is 27000, while the sum is 31.

Adding to 20304153553 its reverse (35535140302), we get a palindrome (55839293855).

The spelling of 20304153553 in words is "twenty billion, three hundred four million, one hundred fifty-three thousand, five hundred fifty-three".

Divisors: 1 96493 210421 20304153553