Search a number
-
+
203043000314122 = 2101521500157061
BaseRepresentation
bin101110001010101010100001…
…111010000110100100001010
3222121220201110210120121202021
4232022222201322012210022
5203103124031040022442
61555500355554555054
760524241554234113
oct5612524172064412
9877821423517667
10203043000314122
11597720643a2511
121a933115b98a8a
13893ab46635827
14381d49577320a
1518719338c1e67
hexb8aaa1e8690a

203043000314122 has 4 divisors (see below), whose sum is σ = 304564500471186. Its totient is φ = 101521500157060.

The previous prime is 203043000314081. The next prime is 203043000314123. The reversal of 203043000314122 is 221413000340302.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 201607937674641 + 1435062639481 = 14198871^2 + 1197941^2 .

It is not an unprimeable number, because it can be changed into a prime (203043000314123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50760750078529 + ... + 50760750078532.

Almost surely, 2203043000314122 is an apocalyptic number.

203043000314122 is a deficient number, since it is larger than the sum of its proper divisors (101521500157064).

203043000314122 is a wasteful number, since it uses less digits than its factorization.

203043000314122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 101521500157063.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 203043000314122 its reverse (221413000340302), we get a palindrome (424456000654424).

The spelling of 203043000314122 in words is "two hundred three trillion, forty-three billion, three hundred fourteen thousand, one hundred twenty-two".

Divisors: 1 2 101521500157061 203043000314122