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2030500505035 = 54726932120549
BaseRepresentation
bin11101100011000011010…
…000101110010111001011
321012010002001221001011201
4131203003100232113023
5231231431112130120
64152444332405031
7266461460343202
oct35430320562713
97163061831151
102030500505035
11713148666742
12289636616777
1311962452a3a2
14703c3582239
1537c40a1e40a
hex1d8c342e5cb

2030500505035 has 16 divisors (see below), whose sum is σ = 2497693968000. Its totient is φ = 1583928462976.

The previous prime is 2030500504993. The next prime is 2030500505039. The reversal of 2030500505035 is 5305050050302.

It is a cyclic number.

It is not a de Polignac number, because 2030500505035 - 227 = 2030366287307 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2030500504994 and 2030500505012.

It is not an unprimeable number, because it can be changed into a prime (2030500505039) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15997060 + ... + 16123489.

It is an arithmetic number, because the mean of its divisors is an integer number (156105873000).

Almost surely, 22030500505035 is an apocalyptic number.

2030500505035 is a deficient number, since it is larger than the sum of its proper divisors (467193462965).

2030500505035 is a wasteful number, since it uses less digits than its factorization.

2030500505035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32120870.

The product of its (nonzero) digits is 11250, while the sum is 28.

Adding to 2030500505035 its reverse (5305050050302), we get a palindrome (7335550555337).

The spelling of 2030500505035 in words is "two trillion, thirty billion, five hundred million, five hundred five thousand, thirty-five".

Divisors: 1 5 47 235 269 1345 12643 63215 32120549 160602745 1509665803 7548329015 8640427681 43202138405 406100101007 2030500505035