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203114144320130 = 25147113807895603
BaseRepresentation
bin101110001011101100110010…
…011010111100101010000010
3222122011112002221120120211202
4232023230302122330222002
5203110310231421221010
61555553203313541202
760532340562301211
oct5613546232745202
9878145087516752
10203114144320130
115979a25232619a
121a944a6bb74802
138944773a9abc4
143822ac42a1078
1518736e965c6a5
hexb8bb326bca82

203114144320130 has 16 divisors (see below), whose sum is σ = 365854001923584. Its totient is φ = 81190426139760.

The previous prime is 203114144320111. The next prime is 203114144320201. The reversal of 203114144320130 is 31023441411302.

203114144320130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 203114144320093 and 203114144320102.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6903933092 + ... + 6903962511.

It is an arithmetic number, because the mean of its divisors is an integer number (22865875120224).

Almost surely, 2203114144320130 is an apocalyptic number.

203114144320130 is a deficient number, since it is larger than the sum of its proper divisors (162739857603454).

203114144320130 is a wasteful number, since it uses less digits than its factorization.

203114144320130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13807897081.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 203114144320130 its reverse (31023441411302), we get a palindrome (234137585731432).

The spelling of 203114144320130 in words is "two hundred three trillion, one hundred fourteen billion, one hundred forty-four million, three hundred twenty thousand, one hundred thirty".

Divisors: 1 2 5 10 1471 2942 7355 14710 13807895603 27615791206 69039478015 138078956030 20311414432013 40622828864026 101557072160065 203114144320130