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203122312441 is a prime number
BaseRepresentation
bin1011110100101100001…
…0001000010011111001
3201102021221110120221221
42331023002020103321
511311443302444231
6233151344032041
720450363111506
oct2751302102371
9642257416857
10203122312441
1179164282804
1233449302621
131620115a029
149b8ca464ad
15543c628d11
hex2f4b0884f9

203122312441 has 2 divisors, whose sum is σ = 203122312442. Its totient is φ = 203122312440.

The previous prime is 203122312417. The next prime is 203122312451. The reversal of 203122312441 is 144213221302.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 202706152441 + 416160000 = 450229^2 + 20400^2 .

It is a cyclic number.

It is not a de Polignac number, because 203122312441 - 211 = 203122310393 is a prime.

It is a super-2 number, since 2×2031223124412 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (203122312451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101561156220 + 101561156221.

It is an arithmetic number, because the mean of its divisors is an integer number (101561156221).

Almost surely, 2203122312441 is an apocalyptic number.

It is an amenable number.

203122312441 is a deficient number, since it is larger than the sum of its proper divisors (1).

203122312441 is an equidigital number, since it uses as much as digits as its factorization.

203122312441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 203122312441 its reverse (144213221302), we get a palindrome (347335533743).

The spelling of 203122312441 in words is "two hundred three billion, one hundred twenty-two million, three hundred twelve thousand, four hundred forty-one".