Base | Representation |
---|---|
bin | 1001001111001100001000… |
… | …11000100001101001001011 |
3 | 2122220220201100112220201212 |
4 | 10213212010120201221023 |
5 | 10130302233032131210 |
6 | 111111415155403335 |
7 | 4164401040505355 |
oct | 447460430415113 |
9 | 78826640486655 |
10 | 20313121364555 |
11 | 65218234a2778 |
12 | 234099b2b354b |
13 | b44699698386 |
14 | 503235cbc0d5 |
15 | 2535ce46b805 |
hex | 127984621a4b |
20313121364555 has 16 divisors (see below), whose sum is σ = 24666956516160. Its totient is φ = 16056899561472.
The previous prime is 20313121364533. The next prime is 20313121364579. The reversal of 20313121364555 is 55546312131302.
It is a cyclic number.
It is not a de Polignac number, because 20313121364555 - 222 = 20313117170251 is a prime.
It is a super-2 number, since 2×203131213645552 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 33641375 + ... + 34239864.
It is an arithmetic number, because the mean of its divisors is an integer number (1541684782260).
Almost surely, 220313121364555 is an apocalyptic number.
20313121364555 is a deficient number, since it is larger than the sum of its proper divisors (4353835151605).
20313121364555 is an equidigital number, since it uses as much as digits as its factorization.
20313121364555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 67881958.
The product of its (nonzero) digits is 324000, while the sum is 41.
Adding to 20313121364555 its reverse (55546312131302), we get a palindrome (75859433495857).
The spelling of 20313121364555 in words is "twenty trillion, three hundred thirteen billion, one hundred twenty-one million, three hundred sixty-four thousand, five hundred fifty-five".
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