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203132000017 is a prime number
BaseRepresentation
bin1011110100101110011…
…1000101011100010001
3201102022121200202211001
42331023213011130101
511312003243000032
6233152331422001
720450541340252
oct2751347053421
9642277622731
10203132000017
117916979a171
12334505b4901
131620316c61b
149b90048b29
15543d3de3e7
hex2f4b9c5711

203132000017 has 2 divisors, whose sum is σ = 203132000018. Its totient is φ = 203132000016.

The previous prime is 203132000003. The next prime is 203132000023. The reversal of 203132000017 is 710000231302.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 202845747456 + 286252561 = 450384^2 + 16919^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-203132000017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 203131999958 and 203132000003.

It is not a weakly prime, because it can be changed into another prime (203132010017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101566000008 + 101566000009.

It is an arithmetic number, because the mean of its divisors is an integer number (101566000009).

Almost surely, 2203132000017 is an apocalyptic number.

It is an amenable number.

203132000017 is a deficient number, since it is larger than the sum of its proper divisors (1).

203132000017 is an equidigital number, since it uses as much as digits as its factorization.

203132000017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 19.

Adding to 203132000017 its reverse (710000231302), we get a palindrome (913132231319).

The spelling of 203132000017 in words is "two hundred three billion, one hundred thirty-two million, seventeen", and thus it is an aban number.