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203140343401 = 1271599530263
BaseRepresentation
bin1011110100110000011…
…0111010011001101001
3201102100012101122210021
42331030012322121221
511312012411442101
6233153230320441
720451002300062
oct2751406723151
9642305348707
10203140343401
1179173478726
1233453359121
1316204b01138
149b911bb569
15543dedb5a1
hex2f4c1ba669

203140343401 has 4 divisors (see below), whose sum is σ = 204739873792. Its totient is φ = 201540813012.

The previous prime is 203140343381. The next prime is 203140343459. The reversal of 203140343401 is 104343041302.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 203140343401 - 25 = 203140343369 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (203140341401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 799765005 + ... + 799765258.

It is an arithmetic number, because the mean of its divisors is an integer number (51184968448).

Almost surely, 2203140343401 is an apocalyptic number.

It is an amenable number.

203140343401 is a deficient number, since it is larger than the sum of its proper divisors (1599530391).

203140343401 is a wasteful number, since it uses less digits than its factorization.

203140343401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1599530390.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 203140343401 its reverse (104343041302), we get a palindrome (307483384703).

The spelling of 203140343401 in words is "two hundred three billion, one hundred forty million, three hundred forty-three thousand, four hundred one".

Divisors: 1 127 1599530263 203140343401