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2031454043011 = 31139034713427
BaseRepresentation
bin11101100011111100000…
…110001011101110000011
321012012112112011210101001
4131203330012023232003
5231240404213334021
64153123114152431
7266524216313251
oct35437406135603
97165475153331
102031454043011
11713597935958
12289861a22717
13119746c4a643
14704740775d1
1537c995c4091
hex1d8fc18bb83

2031454043011 has 8 divisors (see below), whose sum is σ = 2097136093184. Its totient is φ = 1965781447560.

The previous prime is 2031454042993. The next prime is 2031454043057. The reversal of 2031454043011 is 1103404541302.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2031454043011 - 219 = 2031453518723 is a prime.

It is a super-2 number, since 2×20314540430112 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2031454043071) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1925721 + ... + 2787706.

It is an arithmetic number, because the mean of its divisors is an integer number (262142011648).

Almost surely, 22031454043011 is an apocalyptic number.

2031454043011 is a deficient number, since it is larger than the sum of its proper divisors (65682050173).

2031454043011 is a wasteful number, since it uses less digits than its factorization.

2031454043011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4727361.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 2031454043011 its reverse (1103404541302), we get a palindrome (3134858584313).

The spelling of 2031454043011 in words is "two trillion, thirty-one billion, four hundred fifty-four million, forty-three thousand, eleven".

Divisors: 1 31 13903 430993 4713427 146116237 65530775581 2031454043011