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20315115125401 = 49434109875607
BaseRepresentation
bin1001001111001111110110…
…01110000111101010011001
32122221002212022011110110011
410213213323032013222121
510130320323433003101
6111112345100521521
74164501330263245
oct447477316075231
978832768143404
1020315115125401
116522656968808
122341256b502a1
13b44926769915
145033849d1425
152536994ea751
hex1279fb387a99

20315115125401 has 4 divisors (see below), whose sum is σ = 20319225005952. Its totient is φ = 20311005244852.

The previous prime is 20315115125359. The next prime is 20315115125419. The reversal of 20315115125401 is 10452151151302.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20315115125401 - 27 = 20315115125273 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20315115125491) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2054932861 + ... + 2054942746.

It is an arithmetic number, because the mean of its divisors is an integer number (5079806251488).

Almost surely, 220315115125401 is an apocalyptic number.

It is an amenable number.

20315115125401 is a deficient number, since it is larger than the sum of its proper divisors (4109880551).

20315115125401 is an equidigital number, since it uses as much as digits as its factorization.

20315115125401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4109880550.

The product of its (nonzero) digits is 6000, while the sum is 31.

Adding to 20315115125401 its reverse (10452151151302), we get a palindrome (30767266276703).

The spelling of 20315115125401 in words is "twenty trillion, three hundred fifteen billion, one hundred fifteen million, one hundred twenty-five thousand, four hundred one".

Divisors: 1 4943 4109875607 20315115125401