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20320242433 is a prime number
BaseRepresentation
bin10010111011001011…
…100100101100000001
31221110011010021021121
4102323023210230001
5313103440224213
613200205152241
71316361132211
oct227313445401
957404107247
1020320242433
118688279997
123b3125b681
131bbab422ba
14daaa48241
157dde2788d
hex4bb2e4b01

20320242433 has 2 divisors, whose sum is σ = 20320242434. Its totient is φ = 20320242432.

The previous prime is 20320242427. The next prime is 20320242457. The reversal of 20320242433 is 33424202302.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 18661472449 + 1658769984 = 136607^2 + 40728^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20320242433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20320242398 and 20320242407.

It is not a weakly prime, because it can be changed into another prime (20320242413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10160121216 + 10160121217.

It is an arithmetic number, because the mean of its divisors is an integer number (10160121217).

Almost surely, 220320242433 is an apocalyptic number.

It is an amenable number.

20320242433 is a deficient number, since it is larger than the sum of its proper divisors (1).

20320242433 is an equidigital number, since it uses as much as digits as its factorization.

20320242433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 25.

Adding to 20320242433 its reverse (33424202302), we get a palindrome (53744444735).

The spelling of 20320242433 in words is "twenty billion, three hundred twenty million, two hundred forty-two thousand, four hundred thirty-three".