Base | Representation |
---|---|
bin | 11101100100100100100… |
… | …101000101001000011011 |
3 | 21012021021212012010022121 |
4 | 131210210211011020123 |
5 | 231243302101344011 |
6 | 4153314335402111 |
7 | 266550104314453 |
oct | 35444445051033 |
9 | 7167255163277 |
10 | 2032133231131 |
11 | 71390625aa53 |
12 | 289a11383337 |
13 | 119824880bc3 |
14 | 704da354d63 |
15 | 37cd9034e71 |
hex | 1d92494521b |
2032133231131 has 2 divisors, whose sum is σ = 2032133231132. Its totient is φ = 2032133231130.
The previous prime is 2032133231123. The next prime is 2032133231197. The reversal of 2032133231131 is 1311323312302.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2032133231131 - 23 = 2032133231123 is a prime.
It is a super-2 number, since 2×20321332311312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2032133231096 and 2032133231105.
It is not a weakly prime, because it can be changed into another prime (2032133211131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1016066615565 + 1016066615566.
It is an arithmetic number, because the mean of its divisors is an integer number (1016066615566).
Almost surely, 22032133231131 is an apocalyptic number.
2032133231131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2032133231131 is an equidigital number, since it uses as much as digits as its factorization.
2032133231131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 2032133231131 its reverse (1311323312302), we get a palindrome (3343456543433).
The spelling of 2032133231131 in words is "two trillion, thirty-two billion, one hundred thirty-three million, two hundred thirty-one thousand, one hundred thirty-one".
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