Base | Representation |
---|---|
bin | 1001001111100010100001… |
… | …11111110001100011100011 |
3 | 2122222001202020112012010102 |
4 | 10213301100333301203203 |
5 | 10131001343344440003 |
6 | 111121124201253015 |
7 | 4165305006431003 |
oct | 447612077614343 |
9 | 78861666465112 |
10 | 20325144140003 |
11 | 6526932a9a92a |
12 | 234319579416b |
13 | b458644756a1 |
14 | 503a56948003 |
15 | 253a84bda588 |
hex | 127c50ff18e3 |
20325144140003 has 2 divisors, whose sum is σ = 20325144140004. Its totient is φ = 20325144140002.
The previous prime is 20325144139981. The next prime is 20325144140009. The reversal of 20325144140003 is 30004144152302.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20325144140003 - 234 = 20307964270819 is a prime.
It is a super-2 number, since 2×203251441400032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20325144140009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10162572070001 + 10162572070002.
It is an arithmetic number, because the mean of its divisors is an integer number (10162572070002).
Almost surely, 220325144140003 is an apocalyptic number.
20325144140003 is a deficient number, since it is larger than the sum of its proper divisors (1).
20325144140003 is an equidigital number, since it uses as much as digits as its factorization.
20325144140003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 29.
Adding to 20325144140003 its reverse (30004144152302), we get a palindrome (50329288292305).
The spelling of 20325144140003 in words is "twenty trillion, three hundred twenty-five billion, one hundred forty-four million, one hundred forty thousand, three".
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