Base | Representation |
---|---|
bin | 1001001111101101111001… |
… | …00110000101111100000011 |
3 | 2122222122111101002011012102 |
4 | 10213312330212011330003 |
5 | 10131101342021024441 |
6 | 111124013353221015 |
7 | 4165612121155634 |
oct | 447667446057403 |
9 | 78878441064172 |
10 | 20331244314371 |
11 | 6529483421151 |
12 | 23443b870176b |
13 | b462c7216413 |
14 | 504074b9188b |
15 | 253ce050e69b |
hex | 127dbc985f03 |
20331244314371 has 2 divisors, whose sum is σ = 20331244314372. Its totient is φ = 20331244314370.
The previous prime is 20331244314301. The next prime is 20331244314377. The reversal of 20331244314371 is 17341344213302.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20331244314371 - 222 = 20331240120067 is a prime.
It is a super-2 number, since 2×203312443143712 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20331244314377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10165622157185 + 10165622157186.
It is an arithmetic number, because the mean of its divisors is an integer number (10165622157186).
Almost surely, 220331244314371 is an apocalyptic number.
20331244314371 is a deficient number, since it is larger than the sum of its proper divisors (1).
20331244314371 is an equidigital number, since it uses as much as digits as its factorization.
20331244314371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 145152, while the sum is 38.
Adding to 20331244314371 its reverse (17341344213302), we get a palindrome (37672588527673).
The spelling of 20331244314371 in words is "twenty trillion, three hundred thirty-one billion, two hundred forty-four million, three hundred fourteen thousand, three hundred seventy-one".
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