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2034240113 = 3595666407
BaseRepresentation
bin111100101000000…
…0000101001110001
312020202210002211102
41321100000221301
513131231140423
6533504454145
7101260520123
oct17120005161
95222702742
102034240113
11954303784
1248931a355
132655a5299
1415424d213
15bd8c7c28
hex79400a71

2034240113 has 4 divisors (see below), whose sum is σ = 2039906880. Its totient is φ = 2028573348.

The previous prime is 2034240071. The next prime is 2034240121. The reversal of 2034240113 is 3110424302.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2034240113 - 216 = 2034174577 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2034240413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2832845 + ... + 2833562.

It is an arithmetic number, because the mean of its divisors is an integer number (509976720).

Almost surely, 22034240113 is an apocalyptic number.

It is an amenable number.

2034240113 is a deficient number, since it is larger than the sum of its proper divisors (5666767).

2034240113 is an equidigital number, since it uses as much as digits as its factorization.

2034240113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5666766.

The product of its (nonzero) digits is 576, while the sum is 20.

The square root of 2034240113 is about 45102.5510697566. The cubic root of 2034240113 is about 1267.0703780177.

Adding to 2034240113 its reverse (3110424302), we get a palindrome (5144664415).

The spelling of 2034240113 in words is "two billion, thirty-four million, two hundred forty thousand, one hundred thirteen".

Divisors: 1 359 5666407 2034240113