Search a number
-
+
203471145433 is a prime number
BaseRepresentation
bin1011110101111111010…
…0110100100111011001
3201110012020212010212101
42331133310310213121
511313202103123213
6233250124443401
720462130125353
oct2753764644731
9643166763771
10203471145433
1179323180136
12335260a9561
13162584c4c9a
149bc30cc0d3
15545d081bdd
hex2f5fd349d9

203471145433 has 2 divisors, whose sum is σ = 203471145434. Its totient is φ = 203471145432.

The previous prime is 203471145421. The next prime is 203471145457. The reversal of 203471145433 is 334541174302.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 162411418009 + 41059727424 = 403003^2 + 202632^2 .

It is a cyclic number.

It is not a de Polignac number, because 203471145433 - 213 = 203471137241 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 203471145392 and 203471145401.

It is not a weakly prime, because it can be changed into another prime (203471145413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101735572716 + 101735572717.

It is an arithmetic number, because the mean of its divisors is an integer number (101735572717).

Almost surely, 2203471145433 is an apocalyptic number.

It is an amenable number.

203471145433 is a deficient number, since it is larger than the sum of its proper divisors (1).

203471145433 is an equidigital number, since it uses as much as digits as its factorization.

203471145433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120960, while the sum is 37.

The spelling of 203471145433 in words is "two hundred three billion, four hundred seventy-one million, one hundred forty-five thousand, four hundred thirty-three".