Base | Representation |
---|---|
bin | 1001010000010100110010… |
… | …10001110110001111011001 |
3 | 2200001122101200212021012101 |
4 | 10220022121101312033121 |
5 | 10131422123410003423 |
6 | 111141345442043401 |
7 | 4200251446053001 |
oct | 450123121661731 |
9 | 80048350767171 |
10 | 20352126641113 |
11 | 6537319a01323 |
12 | 2348466049561 |
13 | b4827463a387 |
14 | 505096313001 |
15 | 2546139657ad |
hex | 1282994763d9 |
20352126641113 has 2 divisors, whose sum is σ = 20352126641114. Its totient is φ = 20352126641112.
The previous prime is 20352126641087. The next prime is 20352126641129. The reversal of 20352126641113 is 31114662125302.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 17672707947664 + 2679418693449 = 4203892^2 + 1636893^2 .
It is a cyclic number.
It is not a de Polignac number, because 20352126641113 - 225 = 20352093086681 is a prime.
It is not a weakly prime, because it can be changed into another prime (20352126641713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10176063320556 + 10176063320557.
It is an arithmetic number, because the mean of its divisors is an integer number (10176063320557).
Almost surely, 220352126641113 is an apocalyptic number.
It is an amenable number.
20352126641113 is a deficient number, since it is larger than the sum of its proper divisors (1).
20352126641113 is an equidigital number, since it uses as much as digits as its factorization.
20352126641113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 37.
Adding to 20352126641113 its reverse (31114662125302), we get a palindrome (51466788766415).
The spelling of 20352126641113 in words is "twenty trillion, three hundred fifty-two billion, one hundred twenty-six million, six hundred forty-one thousand, one hundred thirteen".
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