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2040132021253 = 311912029169817
BaseRepresentation
bin11101101100000001010…
…110000010110000000101
321020000221022022202120121
4131230001112002300011
5231411142244140003
64201120153301541
7300252242025334
oct35540126026005
97200838282517
102040132021253
117172403813a7
1228b4841048b1
1311a4caa8c401
1470a587c5d1b
1538106391cbd
hex1db01582c05

2040132021253 has 16 divisors (see below), whose sum is σ = 2118024437760. Its totient is φ = 1963005033600.

The previous prime is 2040132021233. The next prime is 2040132021259. The reversal of 2040132021253 is 3521202310402.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2040132021253 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2040132021259) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11928801 + ... + 12098617.

It is an arithmetic number, because the mean of its divisors is an integer number (132376527360).

Almost surely, 22040132021253 is an apocalyptic number.

It is an amenable number.

2040132021253 is a deficient number, since it is larger than the sum of its proper divisors (77892416507).

2040132021253 is a wasteful number, since it uses less digits than its factorization.

2040132021253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 172068.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 2040132021253 its reverse (3521202310402), we get a palindrome (5561334331655).

The spelling of 2040132021253 in words is "two trillion, forty billion, one hundred thirty-two million, twenty-one thousand, two hundred fifty-three".

Divisors: 1 31 191 2029 5921 62899 169817 387539 5264327 12013709 32435047 344558693 1005486457 10681319483 65810710363 2040132021253