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204013441 is a prime number
BaseRepresentation
bin11000010100011…
…11111110000001
3112012212221211101
430022033332001
5404211412231
632124414401
75025041242
oct1412177601
9465787741
10204013441
11a5184355
12583a7401
1333361018
141d148cc9
1512d9d661
hexc28ff81

204013441 has 2 divisors, whose sum is σ = 204013442. Its totient is φ = 204013440.

The previous prime is 204013423. The next prime is 204013451. The reversal of 204013441 is 144310402.

204013441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 195580225 + 8433216 = 13985^2 + 2904^2 .

It is a cyclic number.

It is not a de Polignac number, because 204013441 - 223 = 195624833 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (204013421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 102006720 + 102006721.

It is an arithmetic number, because the mean of its divisors is an integer number (102006721).

Almost surely, 2204013441 is an apocalyptic number.

It is an amenable number.

204013441 is a deficient number, since it is larger than the sum of its proper divisors (1).

204013441 is an equidigital number, since it uses as much as digits as its factorization.

204013441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 19.

The square root of 204013441 is about 14283.3273784507. The cubic root of 204013441 is about 588.6894601646.

Adding to 204013441 its reverse (144310402), we get a palindrome (348323843).

The spelling of 204013441 in words is "two hundred four million, thirteen thousand, four hundred forty-one".