Base | Representation |
---|---|
bin | 101110011000111001100101… |
… | …110110101010101101110011 |
3 | 222202101020111101011001022212 |
4 | 232120321211312222231303 |
5 | 203220141002300333042 |
6 | 2001530022144322335 |
7 | 60655022436514316 |
oct | 5630714566525563 |
9 | 882336441131285 |
10 | 204021245324147 |
11 | 5a009a19187449 |
12 | 1aa708263133ab |
13 | 89ac175765724 |
14 | 38549767b697d |
15 | 188c0da2a5482 |
hex | b98e65daab73 |
204021245324147 has 2 divisors, whose sum is σ = 204021245324148. Its totient is φ = 204021245324146.
The previous prime is 204021245324119. The next prime is 204021245324189. The reversal of 204021245324147 is 741423542120402.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 204021245324147 - 222 = 204021241129843 is a prime.
It is a super-2 number, since 2×2040212453241472 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (204021245324947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 102010622662073 + 102010622662074.
It is an arithmetic number, because the mean of its divisors is an integer number (102010622662074).
Almost surely, 2204021245324147 is an apocalyptic number.
204021245324147 is a deficient number, since it is larger than the sum of its proper divisors (1).
204021245324147 is an equidigital number, since it uses as much as digits as its factorization.
204021245324147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 430080, while the sum is 41.
Adding to 204021245324147 its reverse (741423542120402), we get a palindrome (945444787444549).
The spelling of 204021245324147 in words is "two hundred four trillion, twenty-one billion, two hundred forty-five million, three hundred twenty-four thousand, one hundred forty-seven".
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