2040241213311 has 16 divisors (see below), whose sum is σ = 3181239899904. Its totient is φ = 1138739281344.

The previous prime is 2040241213259. The next prime is 2040241213319. The reversal of 2040241213311 is 1133121420402.

It is not a de Polignac number, because 2040241213311 - 2¹¹ = 2040241211263 is a prime.

It is a super-3 number, since 3×2040241213311³ (a number of 38 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2040241213319) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1129700766 + ... + 1129702571.

It is an arithmetic number, because the mean of its divisors is an integer number (198827493744).

Almost surely, 2^{2040241213311} is an apocalyptic number.

2040241213311 is a gapful number since it is divisible by the number (21) formed by its first and last digit.

2040241213311 is a deficient number, since it is larger than the sum of its proper divisors (1140998686593).

2040241213311 is a wasteful number, since it uses less digits than its factorization.

2040241213311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2259403390.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 2040241213311 its reverse (1133121420402), we get a palindrome (3173362633713).

The spelling of 2040241213311 in words is "two trillion, forty billion, two hundred forty-one million, two hundred thirteen thousand, three hundred eleven".