Base | Representation |
---|---|
bin | 11101101100001101010… |
… | …101101000101111110011 |
3 | 21020001110022221210122002 |
4 | 131230031111220233303 |
5 | 231412100302210311 |
6 | 4201152142204215 |
7 | 300260234253650 |
oct | 35541525505763 |
9 | 7201408853562 |
10 | 2040333241331 |
11 | 717333a17a90 |
12 | 28b51b58366b |
13 | 11a530682b48 |
14 | 70a77404c27 |
15 | 38118d8c93b |
hex | 1db0d568bf3 |
2040333241331 has 16 divisors (see below), whose sum is σ = 2544615889920. Its totient is φ = 1589355185280.
The previous prime is 2040333241301. The next prime is 2040333241351. The reversal of 2040333241331 is 1331423330402.
It is a cyclic number.
It is not a de Polignac number, because 2040333241331 - 222 = 2040329047027 is a prime.
It is a super-2 number, since 2×20403332413312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2040333241294 and 2040333241303.
It is not an unprimeable number, because it can be changed into a prime (2040333241301) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4051211 + ... + 4526916.
It is an arithmetic number, because the mean of its divisors is an integer number (159038493120).
Almost surely, 22040333241331 is an apocalyptic number.
2040333241331 is a deficient number, since it is larger than the sum of its proper divisors (504282648589).
2040333241331 is a wasteful number, since it uses less digits than its factorization.
2040333241331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8581234.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 2040333241331 its reverse (1331423330402), we get a palindrome (3371756571733).
The spelling of 2040333241331 in words is "two trillion, forty billion, three hundred thirty-three million, two hundred forty-one thousand, three hundred thirty-one".
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