Base | Representation |
---|---|
bin | 1011111000000101010… |
… | …1011110100110010011 |
3 | 201111122102202022012202 |
4 | 2332001111132212103 |
5 | 11320330014313011 |
6 | 233422010513415 |
7 | 20512064615645 |
oct | 2760125364623 |
9 | 644572668182 |
10 | 204033354131 |
11 | 79591566922 |
12 | 3366243586b |
13 | 16317b1b459 |
14 | 9c37a38895 |
15 | 54925d723b |
hex | 2f8155e993 |
204033354131 has 32 divisors (see below), whose sum is σ = 224988917760. Its totient is φ = 184417833600.
The previous prime is 204033354127. The next prime is 204033354143. The reversal of 204033354131 is 131453330402.
It is a cyclic number.
It is not a de Polignac number, because 204033354131 - 22 = 204033354127 is a prime.
It is a super-2 number, since 2×2040333541312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 204033354094 and 204033354103.
It is not an unprimeable number, because it can be changed into a prime (204033354331) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7960685 + ... + 7986273.
It is an arithmetic number, because the mean of its divisors is an integer number (7030903680).
Almost surely, 2204033354131 is an apocalyptic number.
204033354131 is a deficient number, since it is larger than the sum of its proper divisors (20955563629).
204033354131 is a wasteful number, since it uses less digits than its factorization.
204033354131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25907.
The product of its (nonzero) digits is 12960, while the sum is 29.
Adding to 204033354131 its reverse (131453330402), we get a palindrome (335486684533).
The spelling of 204033354131 in words is "two hundred four billion, thirty-three million, three hundred fifty-four thousand, one hundred thirty-one".
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