Base | Representation |
---|---|
bin | 1001010001110111110111… |
… | …00000110010011110001011 |
3 | 2200020201200102212221102020 |
4 | 10220323323200302132023 |
5 | 10133310040432120210 |
6 | 111222023314535523 |
7 | 4204143466012545 |
oct | 450737340623613 |
9 | 80221612787366 |
10 | 20405314332555 |
11 | 6557932a80109 |
12 | 235682a5975a3 |
13 | b5029c929349 |
14 | 5078a0146695 |
15 | 255bc80c6770 |
hex | 128efb83278b |
20405314332555 has 16 divisors (see below), whose sum is σ = 32662866604320. Its totient is φ = 10878046419968.
The previous prime is 20405314332527. The next prime is 20405314332581. The reversal of 20405314332555 is 55523341350402.
It is a cyclic number.
It is not a de Polignac number, because 20405314332555 - 212 = 20405314328459 is a prime.
It is a super-3 number, since 3×204053143325553 (a number of 41 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 299207940 + ... + 299276129.
It is an arithmetic number, because the mean of its divisors is an integer number (2041429162770).
Almost surely, 220405314332555 is an apocalyptic number.
20405314332555 is a deficient number, since it is larger than the sum of its proper divisors (12257552271765).
20405314332555 is a wasteful number, since it uses less digits than its factorization.
20405314332555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 598486350.
The product of its (nonzero) digits is 1080000, while the sum is 42.
Adding to 20405314332555 its reverse (55523341350402), we get a palindrome (75928655682957).
The spelling of 20405314332555 in words is "twenty trillion, four hundred five billion, three hundred fourteen million, three hundred thirty-two thousand, five hundred fifty-five".
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