Search a number
-
+
20405314332555 = 352273598484069
BaseRepresentation
bin1001010001110111110111…
…00000110010011110001011
32200020201200102212221102020
410220323323200302132023
510133310040432120210
6111222023314535523
74204143466012545
oct450737340623613
980221612787366
1020405314332555
116557932a80109
12235682a5975a3
13b5029c929349
145078a0146695
15255bc80c6770
hex128efb83278b

20405314332555 has 16 divisors (see below), whose sum is σ = 32662866604320. Its totient is φ = 10878046419968.

The previous prime is 20405314332527. The next prime is 20405314332581. The reversal of 20405314332555 is 55523341350402.

It is a cyclic number.

It is not a de Polignac number, because 20405314332555 - 212 = 20405314328459 is a prime.

It is a super-3 number, since 3×204053143325553 (a number of 41 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 299207940 + ... + 299276129.

It is an arithmetic number, because the mean of its divisors is an integer number (2041429162770).

Almost surely, 220405314332555 is an apocalyptic number.

20405314332555 is a deficient number, since it is larger than the sum of its proper divisors (12257552271765).

20405314332555 is a wasteful number, since it uses less digits than its factorization.

20405314332555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 598486350.

The product of its (nonzero) digits is 1080000, while the sum is 42.

Adding to 20405314332555 its reverse (55523341350402), we get a palindrome (75928655682957).

The spelling of 20405314332555 in words is "twenty trillion, four hundred five billion, three hundred fourteen million, three hundred thirty-two thousand, five hundred fifty-five".

Divisors: 1 3 5 15 2273 6819 11365 34095 598484069 1795452207 2992420345 8977261035 1360354288837 4081062866511 6801771444185 20405314332555