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20411324121 = 36803774707
BaseRepresentation
bin10011000000100111…
…000001011011011001
31221200111111200212110
4103000213001123121
5313300244332441
613213221302533
71321545251406
oct230047013331
957614450773
1020411324121
118724729a11
123b57864a49
131c039826a6
14db8b972ad
157e6e19b16
hex4c09c16d9

20411324121 has 4 divisors (see below), whose sum is σ = 27215098832. Its totient is φ = 13607549412.

The previous prime is 20411324113. The next prime is 20411324137. The reversal of 20411324121 is 12142311402.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 20411324121 - 23 = 20411324113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20411324191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3401887351 + ... + 3401887356.

It is an arithmetic number, because the mean of its divisors is an integer number (6803774708).

Almost surely, 220411324121 is an apocalyptic number.

It is an amenable number.

20411324121 is a deficient number, since it is larger than the sum of its proper divisors (6803774711).

20411324121 is an equidigital number, since it uses as much as digits as its factorization.

20411324121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6803774710.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 20411324121 its reverse (12142311402), we get a palindrome (32553635523).

It can be divided in two parts, 2041132 and 4121, that added together give a triangular number (2045253 = T2022).

The spelling of 20411324121 in words is "twenty billion, four hundred eleven million, three hundred twenty-four thousand, one hundred twenty-one".

Divisors: 1 3 6803774707 20411324121