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20412222433 = 173591175887
BaseRepresentation
bin10011000000101010…
…011100101111100001
31221200120012100010021
4103000222130233201
5313301012104213
613213252433441
71321556012401
oct230052345741
957616170107
1020412222433
118725192919
123b58018881
131c03c08535
14db8d4c801
157e7045d8d
hex4c0a9cbe1

20412222433 has 4 divisors (see below), whose sum is σ = 20413415680. Its totient is φ = 20411029188.

The previous prime is 20412222407. The next prime is 20412222437. The reversal of 20412222433 is 33422221402.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33422221402 = 216711110701.

It is a cyclic number.

It is not a de Polignac number, because 20412222433 - 25 = 20412222401 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20412222398 and 20412222407.

It is not an unprimeable number, because it can be changed into a prime (20412222437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 570585 + ... + 605302.

It is an arithmetic number, because the mean of its divisors is an integer number (5103353920).

Almost surely, 220412222433 is an apocalyptic number.

It is an amenable number.

20412222433 is a deficient number, since it is larger than the sum of its proper divisors (1193247).

20412222433 is a wasteful number, since it uses less digits than its factorization.

20412222433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1193246.

The product of its (nonzero) digits is 4608, while the sum is 25.

Adding to 20412222433 its reverse (33422221402), we get a palindrome (53834443835).

The spelling of 20412222433 in words is "twenty billion, four hundred twelve million, two hundred twenty-two thousand, four hundred thirty-three".

Divisors: 1 17359 1175887 20412222433