Base | Representation |
---|---|
bin | 1001010010000110011000… |
… | …01110101110110001101011 |
3 | 2200021110210210200220100012 |
4 | 10221003030032232301223 |
5 | 10133422022404114032 |
6 | 111225353112402135 |
7 | 4204540630434062 |
oct | 451031416566153 |
9 | 80243723626305 |
10 | 20413111004267 |
11 | 6560173aa1a53 |
12 | 23582456a634b |
13 | b50c42cbb267 |
14 | 507ddd8031d9 |
15 | 255ed280b6b2 |
hex | 1290cc3aec6b |
20413111004267 has 2 divisors, whose sum is σ = 20413111004268. Its totient is φ = 20413111004266.
The previous prime is 20413111004233. The next prime is 20413111004327. The reversal of 20413111004267 is 76240011131402.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20413111004267 - 232 = 20408816036971 is a prime.
It is not a weakly prime, because it can be changed into another prime (20413111004207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10206555502133 + 10206555502134.
It is an arithmetic number, because the mean of its divisors is an integer number (10206555502134).
Almost surely, 220413111004267 is an apocalyptic number.
20413111004267 is a deficient number, since it is larger than the sum of its proper divisors (1).
20413111004267 is an equidigital number, since it uses as much as digits as its factorization.
20413111004267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 32.
Adding to 20413111004267 its reverse (76240011131402), we get a palindrome (96653122135669).
The spelling of 20413111004267 in words is "twenty trillion, four hundred thirteen billion, one hundred eleven million, four thousand, two hundred sixty-seven".
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