Base | Representation |
---|---|
bin | 11101101101001101001… |
… | …011011110100101110001 |
3 | 21020011012222101020111121 |
4 | 131231031023132211301 |
5 | 231421244001220423 |
6 | 4201450323142241 |
7 | 300325621263424 |
oct | 35551513364561 |
9 | 7204188336447 |
10 | 2041404320113 |
11 | 717833579364 |
12 | 28b77a214981 |
13 | 11a671548882 |
14 | 70b397759bb |
15 | 3817ce0e45d |
hex | 1db4d2de971 |
2041404320113 has 2 divisors, whose sum is σ = 2041404320114. Its totient is φ = 2041404320112.
The previous prime is 2041404320099. The next prime is 2041404320147. The reversal of 2041404320113 is 3110234041402.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2033541596529 + 7862723584 = 1426023^2 + 88672^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2041404320113 is a prime.
It is not a weakly prime, because it can be changed into another prime (2041404320183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1020702160056 + 1020702160057.
It is an arithmetic number, because the mean of its divisors is an integer number (1020702160057).
Almost surely, 22041404320113 is an apocalyptic number.
It is an amenable number.
2041404320113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2041404320113 is an equidigital number, since it uses as much as digits as its factorization.
2041404320113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 2041404320113 its reverse (3110234041402), we get a palindrome (5151638361515).
The spelling of 2041404320113 in words is "two trillion, forty-one billion, four hundred four million, three hundred twenty thousand, one hundred thirteen".
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