Base | Representation |
---|---|
bin | 1001010010001000101011… |
… | …01111100000000010010011 |
3 | 2200021120222202102102010022 |
4 | 10221010111233200002103 |
5 | 10133432034122101121 |
6 | 111230115331054055 |
7 | 4204613324516042 |
oct | 451042557400223 |
9 | 80246882372108 |
10 | 20414344331411 |
11 | 65607471a0988 |
12 | 235852a74132b |
13 | b510ab680c34 |
14 | 5080b952a559 |
15 | 256055c2baab |
hex | 129115be0093 |
20414344331411 has 4 divisors (see below), whose sum is σ = 20415730907592. Its totient is φ = 20412957755232.
The previous prime is 20414344331387. The next prime is 20414344331431. The reversal of 20414344331411 is 11413344341402.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20414344331411 - 230 = 20413270589587 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20414344331431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 693266006 + ... + 693295451.
It is an arithmetic number, because the mean of its divisors is an integer number (5103932726898).
Almost surely, 220414344331411 is an apocalyptic number.
20414344331411 is a deficient number, since it is larger than the sum of its proper divisors (1386576181).
20414344331411 is a wasteful number, since it uses less digits than its factorization.
20414344331411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1386576180.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 20414344331411 its reverse (11413344341402), we get a palindrome (31827688672813).
Subtracting from 20414344331411 its reverse (11413344341402), we obtain a palindrome (9000999990009).
The spelling of 20414344331411 in words is "twenty trillion, four hundred fourteen billion, three hundred forty-four million, three hundred thirty-one thousand, four hundred eleven".
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