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204213131483 is a prime number
BaseRepresentation
bin1011111000110000001…
…1010001100011011011
3201112002222000221101012
42332030003101203123
511321212030201413
6233451512044135
720516406656114
oct2761403214333
9645088027335
10204213131483
1179673a97249
12336b269364b
1316346144b9a
149c5387520b
1554a32997a8
hex2f8c0d18db

204213131483 has 2 divisors, whose sum is σ = 204213131484. Its totient is φ = 204213131482.

The previous prime is 204213131477. The next prime is 204213131597. The reversal of 204213131483 is 384131312402.

204213131483 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 204213131483 - 24 = 204213131467 is a prime.

It is not a weakly prime, because it can be changed into another prime (204213131443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 102106565741 + 102106565742.

It is an arithmetic number, because the mean of its divisors is an integer number (102106565742).

Almost surely, 2204213131483 is an apocalyptic number.

204213131483 is a deficient number, since it is larger than the sum of its proper divisors (1).

204213131483 is an equidigital number, since it uses as much as digits as its factorization.

204213131483 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 32.

Adding to 204213131483 its reverse (384131312402), we get a palindrome (588344443885).

The spelling of 204213131483 in words is "two hundred four billion, two hundred thirteen million, one hundred thirty-one thousand, four hundred eighty-three".