2043314000131 has 4 divisors (see below), whose sum is σ = 2043320715000. Its totient is φ = 2043307285264.

The previous prime is 2043314000113. The next prime is 2043314000177. The reversal of 2043314000131 is 1310004133402.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2043314000131 - 2⁵ = 2043314000099 is a prime.

It is a super-2 number, since 2×2043314000131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2043314009131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2878186 + ... + 3517183.

It is an arithmetic number, because the mean of its divisors is an integer number (510830178750).

Almost surely, 2^{2043314000131} is an apocalyptic number.

2043314000131 is a deficient number, since it is larger than the sum of its proper divisors (6714869).

2043314000131 is an equidigital number, since it uses as much as digits as its factorization.

2043314000131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6714868.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 2043314000131 its reverse (1310004133402), we get a palindrome (3353318133533).

The spelling of 2043314000131 in words is "two trillion, forty-three billion, three hundred fourteen million, one hundred thirty-one", and thus it is an aban number.