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2050115113 = 9059226307
BaseRepresentation
bin111101000110010…
…0100011000101001
312021212122122020101
41322030210120221
513144312140423
6535233025401
7101542455664
oct17214443051
95255578211
102050115113
11962266912
124926b5261
13268972c87
141563c26db
15beeb17ad
hex7a324629

2050115113 has 4 divisors (see below), whose sum is σ = 2050350480. Its totient is φ = 2049879748.

The previous prime is 2050115107. The next prime is 2050115147. The reversal of 2050115113 is 3115110502.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2050115113 - 213 = 2050106921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2050115173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 104095 + ... + 122212.

It is an arithmetic number, because the mean of its divisors is an integer number (512587620).

Almost surely, 22050115113 is an apocalyptic number.

It is an amenable number.

2050115113 is a deficient number, since it is larger than the sum of its proper divisors (235367).

2050115113 is an equidigital number, since it uses as much as digits as its factorization.

2050115113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 235366.

The product of its (nonzero) digits is 150, while the sum is 19.

The square root of 2050115113 is about 45278.1968832682. The cubic root of 2050115113 is about 1270.3578698833.

Adding to 2050115113 its reverse (3115110502), we get a palindrome (5165225615).

The spelling of 2050115113 in words is "two billion, fifty million, one hundred fifteen thousand, one hundred thirteen".

Divisors: 1 9059 226307 2050115113