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205145405131 is a prime number
BaseRepresentation
bin1011111100001110011…
…1100111011011001011
3201121111221021100101211
42333003213213123023
511330114210431011
6234124213553551
720551460113102
oct2770347473313
9647457240354
10205145405131
117a002262237
12339129458b7
131646432b3b4
149d015d3039
15550a04db21
hex2fc39e76cb

205145405131 has 2 divisors, whose sum is σ = 205145405132. Its totient is φ = 205145405130.

The previous prime is 205145405099. The next prime is 205145405137. The reversal of 205145405131 is 131504541502.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 205145405131 - 25 = 205145405099 is a prime.

It is a super-2 number, since 2×2051454051312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 205145405093 and 205145405102.

It is not a weakly prime, because it can be changed into another prime (205145405137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 102572702565 + 102572702566.

It is an arithmetic number, because the mean of its divisors is an integer number (102572702566).

Almost surely, 2205145405131 is an apocalyptic number.

205145405131 is a deficient number, since it is larger than the sum of its proper divisors (1).

205145405131 is an equidigital number, since it uses as much as digits as its factorization.

205145405131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 205145405131 its reverse (131504541502), we get a palindrome (336649946633).

The spelling of 205145405131 in words is "two hundred five billion, one hundred forty-five million, four hundred five thousand, one hundred thirty-one".