Base | Representation |
---|---|
bin | 11101110111001100100… |
… | …100011011011111010011 |
3 | 21021011220120110112200202 |
4 | 131313030210123133103 |
5 | 232110231131031120 |
6 | 4210423004005415 |
7 | 301155505650326 |
oct | 35671444333723 |
9 | 7234816415622 |
10 | 2052131502035 |
11 | 72133880896a |
12 | 29187283086b |
13 | 11b690aa17b4 |
14 | 7147630a7bd |
15 | 385a9a5d875 |
hex | 1ddcc91b7d3 |
2052131502035 has 16 divisors (see below), whose sum is σ = 2504358470880. Its totient is φ = 1613839476480.
The previous prime is 2052131502023. The next prime is 2052131502041. The reversal of 2052131502035 is 5302051312502.
It is not a de Polignac number, because 2052131502035 - 24 = 2052131502019 is a prime.
It is a super-2 number, since 2×20521315020352 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2052131501989 and 2052131502007.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18563225 + ... + 18673445.
It is an arithmetic number, because the mean of its divisors is an integer number (156522404430).
Almost surely, 22052131502035 is an apocalyptic number.
2052131502035 is a deficient number, since it is larger than the sum of its proper divisors (452226968845).
2052131502035 is a wasteful number, since it uses less digits than its factorization.
2052131502035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 173398.
The product of its (nonzero) digits is 9000, while the sum is 29.
Adding to 2052131502035 its reverse (5302051312502), we get a palindrome (7354182814537).
The spelling of 2052131502035 in words is "two trillion, fifty-two billion, one hundred thirty-one million, five hundred two thousand, thirty-five".
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