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205314012032257 is a prime number
BaseRepresentation
bin101110101011101101100100…
…110000010010110100000001
3222220221211100111210012110101
4232223231210300102310001
5203402331044040013012
62004355542141402401
761150306421313322
oct5653554460226401
9886854314705411
10205314012032257
115a4682022a3357
121b03b293269401
138a7404a11449b
14389b373438449
1518b0a4e17cd57
hexbabb64c12d01

205314012032257 has 2 divisors, whose sum is σ = 205314012032258. Its totient is φ = 205314012032256.

The previous prime is 205314012032183. The next prime is 205314012032287. The reversal of 205314012032257 is 752230210413502.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 172466338430736 + 32847673601521 = 13132644^2 + 5731289^2 .

It is a cyclic number.

It is not a de Polignac number, because 205314012032257 - 215 = 205314011999489 is a prime.

It is not a weakly prime, because it can be changed into another prime (205314012032287) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 102657006016128 + 102657006016129.

It is an arithmetic number, because the mean of its divisors is an integer number (102657006016129).

Almost surely, 2205314012032257 is an apocalyptic number.

It is an amenable number.

205314012032257 is a deficient number, since it is larger than the sum of its proper divisors (1).

205314012032257 is an equidigital number, since it uses as much as digits as its factorization.

205314012032257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 100800, while the sum is 37.

Adding to 205314012032257 its reverse (752230210413502), we get a palindrome (957544222445759).

The spelling of 205314012032257 in words is "two hundred five trillion, three hundred fourteen billion, twelve million, thirty-two thousand, two hundred fifty-seven".