Base | Representation |
---|---|
bin | 101110101101001001111101… |
… | …100110010111111111101011 |
3 | 222221022022102000010002202011 |
4 | 232231021331212113333223 |
5 | 203410442230024012001 |
6 | 2004513305525020351 |
7 | 61160420624465206 |
oct | 5655117546277753 |
9 | 887268360102664 |
10 | 205413213110251 |
11 | 5a4a6288764533 |
12 | 1b0565595546b7 |
13 | 8a804c925a8c3 |
14 | 38a20a433093d |
15 | 18b34081a4d51 |
hex | bad27d997feb |
205413213110251 has 4 divisors (see below), whose sum is σ = 205434435685600. Its totient is φ = 205391990534904.
The previous prime is 205413213110221. The next prime is 205413213110257. The reversal of 205413213110251 is 152011312314502.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 205413213110251 - 27 = 205413213110123 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (205413213110257) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10611273156 + ... + 10611292513.
It is an arithmetic number, because the mean of its divisors is an integer number (51358608921400).
Almost surely, 2205413213110251 is an apocalyptic number.
205413213110251 is a deficient number, since it is larger than the sum of its proper divisors (21222575349).
205413213110251 is an equidigital number, since it uses as much as digits as its factorization.
205413213110251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21222575348.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 205413213110251 its reverse (152011312314502), we get a palindrome (357424525424753).
The spelling of 205413213110251 in words is "two hundred five trillion, four hundred thirteen billion, two hundred thirteen million, one hundred ten thousand, two hundred fifty-one".
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