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205433113 is a prime number
BaseRepresentation
bin11000011111010…
…10100100011001
3112022120002020211
430033222210121
5410042324423
632215051121
75043103234
oct1417524431
9468502224
10205433113
11a5a63a36
1258970aa1
133373a272
141d3d841b
151307e10d
hexc3ea919

205433113 has 2 divisors, whose sum is σ = 205433114. Its totient is φ = 205433112.

The previous prime is 205433089. The next prime is 205433119. The reversal of 205433113 is 311334502.

205433113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 180552969 + 24880144 = 13437^2 + 4988^2 .

It is a cyclic number.

It is not a de Polignac number, because 205433113 - 221 = 203335961 is a prime.

It is not a weakly prime, because it can be changed into another prime (205433119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 102716556 + 102716557.

It is an arithmetic number, because the mean of its divisors is an integer number (102716557).

Almost surely, 2205433113 is an apocalyptic number.

It is an amenable number.

205433113 is a deficient number, since it is larger than the sum of its proper divisors (1).

205433113 is an equidigital number, since it uses as much as digits as its factorization.

205433113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1080, while the sum is 22.

The square root of 205433113 is about 14332.9380449369. The cubic root of 205433113 is about 590.0518129351.

Adding to 205433113 its reverse (311334502), we get a palindrome (516767615).

The spelling of 205433113 in words is "two hundred five million, four hundred thirty-three thousand, one hundred thirteen".