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205455113153 = 424267484259
BaseRepresentation
bin1011111101011000010…
…1000011101111000001
3201122022112001010221022
42333112011003233001
511331233002110103
6234215040035225
720562240434663
oct2772605035701
9648275033838
10205455113153
117a151067484
123399a602b15
13164b3547b94
149d307b2533
155527329138
hex2fd6143bc1

205455113153 has 4 divisors (see below), whose sum is σ = 205456021680. Its totient is φ = 205454204628.

The previous prime is 205455113137. The next prime is 205455113159. The reversal of 205455113153 is 351311554502.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 205455113153 - 24 = 205455113137 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (205455113159) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 182138 + ... + 666396.

It is an arithmetic number, because the mean of its divisors is an integer number (51364005420).

Almost surely, 2205455113153 is an apocalyptic number.

It is an amenable number.

205455113153 is a deficient number, since it is larger than the sum of its proper divisors (908527).

205455113153 is an equidigital number, since it uses as much as digits as its factorization.

205455113153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 908526.

The product of its (nonzero) digits is 45000, while the sum is 35.

Adding to 205455113153 its reverse (351311554502), we get a palindrome (556766667655).

The spelling of 205455113153 in words is "two hundred five billion, four hundred fifty-five million, one hundred thirteen thousand, one hundred fifty-three".

Divisors: 1 424267 484259 205455113153