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21000013233 = 37000004411
BaseRepresentation
bin10011100011101100…
…101100010110110001
32000012112020012111220
4103203230230112301
5321002000410413
613351451055253
71342254111243
oct234354542661
960175205456
1021000013233
1189a6a61841
1240a0a41529
131c9891ab44
141033038093
1582d951223
hex4e3b2c5b1

21000013233 has 4 divisors (see below), whose sum is σ = 28000017648. Its totient is φ = 14000008820.

The previous prime is 21000013103. The next prime is 21000013241. The reversal of 21000013233 is 33231000012.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21000013233 - 217 = 20999882161 is a prime.

It is a super-2 number, since 2×210000132332 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (21000013253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3500002203 + ... + 3500002208.

It is an arithmetic number, because the mean of its divisors is an integer number (7000004412).

Almost surely, 221000013233 is an apocalyptic number.

It is an amenable number.

21000013233 is a deficient number, since it is larger than the sum of its proper divisors (7000004415).

21000013233 is an equidigital number, since it uses as much as digits as its factorization.

21000013233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7000004414.

The product of its (nonzero) digits is 108, while the sum is 15.

Adding to 21000013233 its reverse (33231000012), we get a palindrome (54231013245).

The spelling of 21000013233 in words is "twenty-one billion, thirteen thousand, two hundred thirty-three".

Divisors: 1 3 7000004411 21000013233