Base | Representation |
---|---|
bin | 11110100011110111101… |
… | …110111010100100010001 |
3 | 21102202201121020112110121 |
4 | 132203313232322210101 |
5 | 233402001134430223 |
6 | 4244434530030241 |
7 | 304504305053254 |
oct | 36436756724421 |
9 | 7382647215417 |
10 | 2100100311313 |
11 | 73a7139702a4 |
12 | 29b01b418381 |
13 | 123066a96204 |
14 | 73906d8309b |
15 | 39965e2e15d |
hex | 1e8f7bba911 |
2100100311313 has 2 divisors, whose sum is σ = 2100100311314. Its totient is φ = 2100100311312.
The previous prime is 2100100311307. The next prime is 2100100311317. The reversal of 2100100311313 is 3131130010012.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2008319791104 + 91780520209 = 1417152^2 + 302953^2 .
It is a cyclic number.
It is not a de Polignac number, because 2100100311313 - 29 = 2100100310801 is a prime.
It is not a weakly prime, because it can be changed into another prime (2100100311317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050050155656 + 1050050155657.
It is an arithmetic number, because the mean of its divisors is an integer number (1050050155657).
Almost surely, 22100100311313 is an apocalyptic number.
It is an amenable number.
2100100311313 is a deficient number, since it is larger than the sum of its proper divisors (1).
2100100311313 is an equidigital number, since it uses as much as digits as its factorization.
2100100311313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 2100100311313 its reverse (3131130010012), we get a palindrome (5231230321325).
The spelling of 2100100311313 in words is "two trillion, one hundred billion, one hundred million, three hundred eleven thousand, three hundred thirteen".
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