Base | Representation |
---|---|
bin | 11110100011110111110… |
… | …110001010101000010001 |
3 | 21102202201201211002212121 |
4 | 132203313312022220101 |
5 | 233402002131241423 |
6 | 4244435034454241 |
7 | 304504330161043 |
oct | 36436766125021 |
9 | 7382651732777 |
10 | 2100102212113 |
11 | 73a714a49404 |
12 | 29b01bb94381 |
13 | 1230672b0449 |
14 | 73907319a93 |
15 | 399661a745d |
hex | 1e8f7d8aa11 |
2100102212113 has 16 divisors (see below), whose sum is σ = 2205864760320. Its totient is φ = 1995555435984.
The previous prime is 2100102212077. The next prime is 2100102212123. The reversal of 2100102212113 is 3112122010012.
It is a cyclic number.
It is not a de Polignac number, because 2100102212113 - 213 = 2100102203921 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2100102212123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8131908 + ... + 8386186.
It is an arithmetic number, because the mean of its divisors is an integer number (137866547520).
Almost surely, 22100102212113 is an apocalyptic number.
2100102212113 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
2100102212113 is a deficient number, since it is larger than the sum of its proper divisors (105762548207).
2100102212113 is a wasteful number, since it uses less digits than its factorization.
2100102212113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 256668.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 2100102212113 its reverse (3112122010012), we get a palindrome (5212224222125).
The spelling of 2100102212113 in words is "two trillion, one hundred billion, one hundred two million, two hundred twelve thousand, one hundred thirteen".
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