Base | Representation |
---|---|
bin | 11110100011111000010… |
… | …100010101110001000011 |
3 | 21102202202021200222021021 |
4 | 132203320110111301003 |
5 | 233402011142401201 |
6 | 4244435520210311 |
7 | 304504454334064 |
oct | 36437024256103 |
9 | 7382667628237 |
10 | 2100110122051 |
11 | 73a719461247 |
12 | 29b022769997 |
13 | 123068b1c896 |
14 | 739083b856b |
15 | 39966c1aea1 |
hex | 1e8f8515c43 |
2100110122051 has 2 divisors, whose sum is σ = 2100110122052. Its totient is φ = 2100110122050.
The previous prime is 2100110122021. The next prime is 2100110122069. The reversal of 2100110122051 is 1502210110012.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2100110122051 is a prime.
It is a super-2 number, since 2×21001101220512 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2100110122021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050055061025 + 1050055061026.
It is an arithmetic number, because the mean of its divisors is an integer number (1050055061026).
Almost surely, 22100110122051 is an apocalyptic number.
2100110122051 is a deficient number, since it is larger than the sum of its proper divisors (1).
2100110122051 is an equidigital number, since it uses as much as digits as its factorization.
2100110122051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 16.
Adding to 2100110122051 its reverse (1502210110012), we get a palindrome (3602320232063).
The spelling of 2100110122051 in words is "two trillion, one hundred billion, one hundred ten million, one hundred twenty-two thousand, fifty-one".
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