Base | Representation |
---|---|
bin | 11110100011111001001… |
… | …001110100111010001001 |
3 | 21102202210021002022201121 |
4 | 132203321021310322021 |
5 | 233402023240040431 |
6 | 4244441140515241 |
7 | 304505014452145 |
oct | 36437111647211 |
9 | 7382707068647 |
10 | 2100124143241 |
11 | 73a726368603 |
12 | 29b0273abb21 |
13 | 12306b9bb847 |
14 | 7390a1c8225 |
15 | 3996808a611 |
hex | 1e8f9274e89 |
2100124143241 has 2 divisors, whose sum is σ = 2100124143242. Its totient is φ = 2100124143240.
The previous prime is 2100124143197. The next prime is 2100124143269. The reversal of 2100124143241 is 1423414210012.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1580290353216 + 519833790025 = 1257096^2 + 720995^2 .
It is a cyclic number.
It is not a de Polignac number, because 2100124143241 - 219 = 2100123618953 is a prime.
It is not a weakly prime, because it can be changed into another prime (2100124143841) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050062071620 + 1050062071621.
It is an arithmetic number, because the mean of its divisors is an integer number (1050062071621).
Almost surely, 22100124143241 is an apocalyptic number.
It is an amenable number.
2100124143241 is a deficient number, since it is larger than the sum of its proper divisors (1).
2100124143241 is an equidigital number, since it uses as much as digits as its factorization.
2100124143241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 2100124143241 its reverse (1423414210012), we get a palindrome (3523538353253).
The spelling of 2100124143241 in words is "two trillion, one hundred billion, one hundred twenty-four million, one hundred forty-three thousand, two hundred forty-one".
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