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210013243441403 is a prime number
BaseRepresentation
bin101111110000000110000100…
…110001100000000011111011
31000112121001220000201211200112
4233300012010301200003323
5210011324110310111103
62022354430243254535
762143645644244343
oct5760060461400373
91015531800654615
10210013243441403
1160a0a130985966
121b679b8237a44b
13902521907345c
1439c09a396bd23
151942dd69becd8
hexbf0184c600fb

210013243441403 has 2 divisors, whose sum is σ = 210013243441404. Its totient is φ = 210013243441402.

The previous prime is 210013243441369. The next prime is 210013243441433. The reversal of 210013243441403 is 304144342310012.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 210013243441403 - 244 = 192421057396987 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 210013243441403.

It is not a weakly prime, because it can be changed into another prime (210013243441433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105006621720701 + 105006621720702.

It is an arithmetic number, because the mean of its divisors is an integer number (105006621720702).

Almost surely, 2210013243441403 is an apocalyptic number.

210013243441403 is a deficient number, since it is larger than the sum of its proper divisors (1).

210013243441403 is an equidigital number, since it uses as much as digits as its factorization.

210013243441403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 210013243441403 its reverse (304144342310012), we get a palindrome (514157585751415).

The spelling of 210013243441403 in words is "two hundred ten trillion, thirteen billion, two hundred forty-three million, four hundred forty-one thousand, four hundred three".