Base | Representation |
---|---|
bin | 1100001110011011010… |
… | …1000100100111100001 |
3 | 202002010102120111010202 |
4 | 3003212311010213201 |
5 | 11420120430234213 |
6 | 240253103234545 |
7 | 21113523625415 |
oct | 3034665044741 |
9 | 662112514122 |
10 | 210031102433 |
11 | 8108a0999a9 |
12 | 34856ba8a55 |
13 | 16a625a9349 |
14 | a24641cd45 |
15 | 56e3e27b58 |
hex | 30e6d449e1 |
210031102433 has 2 divisors, whose sum is σ = 210031102434. Its totient is φ = 210031102432.
The previous prime is 210031102367. The next prime is 210031102439. The reversal of 210031102433 is 334201130012.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 119268694609 + 90762407824 = 345353^2 + 301268^2 .
It is a cyclic number.
It is not a de Polignac number, because 210031102433 - 230 = 208957360609 is a prime.
It is a super-2 number, since 2×2100311024332 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (210031102439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105015551216 + 105015551217.
It is an arithmetic number, because the mean of its divisors is an integer number (105015551217).
Almost surely, 2210031102433 is an apocalyptic number.
It is an amenable number.
210031102433 is a deficient number, since it is larger than the sum of its proper divisors (1).
210031102433 is an equidigital number, since it uses as much as digits as its factorization.
210031102433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 210031102433 its reverse (334201130012), we get a palindrome (544232232445).
The spelling of 210031102433 in words is "two hundred ten billion, thirty-one million, one hundred two thousand, four hundred thirty-three".
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