Base | Representation |
---|---|
bin | 1100001110011011011… |
… | …0011000000010100100 |
3 | 202002010110012211212021 |
4 | 3003212312120002210 |
5 | 11420121022203012 |
6 | 240253114432524 |
7 | 21113526550546 |
oct | 3034666300244 |
9 | 662113184767 |
10 | 210031444132 |
11 | 8108a3026a4 |
12 | 34857132744 |
13 | 16a62698a33 |
14 | a2464ab696 |
15 | 56e3e94007 |
hex | 30e6d980a4 |
210031444132 has 6 divisors (see below), whose sum is σ = 367555027238. Its totient is φ = 105015722064.
The previous prime is 210031444099. The next prime is 210031444153. The reversal of 210031444132 is 231444130012.
210031444132 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in only one way, i.e., 159611436196 + 50420007936 = 399514^2 + 224544^2 .
It is a super-2 number, since 2×2100314441322 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 210031444097 and 210031444106.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26253930513 + ... + 26253930520.
Almost surely, 2210031444132 is an apocalyptic number.
It is an amenable number.
210031444132 is a deficient number, since it is larger than the sum of its proper divisors (157523583106).
210031444132 is a wasteful number, since it uses less digits than its factorization.
210031444132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52507861037 (or 52507861035 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 210031444132 its reverse (231444130012), we get a palindrome (441475574144).
The spelling of 210031444132 in words is "two hundred ten billion, thirty-one million, four hundred forty-four thousand, one hundred thirty-two".
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