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21004104115 = 519325498539
BaseRepresentation
bin10011100011111100…
…010011000110110011
32000012210221001011001
4103203330103012303
5321004022312430
613352114502431
71342333640101
oct234374230663
960183831131
1021004104115
1189a92a6335
1240a2294a17
131c99720b97
1410337c0c71
1582dead3ca
hex4e3f131b3

21004104115 has 16 divisors (see below), whose sum is σ = 25348428000. Its totient is φ = 16707704832.

The previous prime is 21004104113. The next prime is 21004104131. The reversal of 21004104115 is 51140140012.

It is a cyclic number.

It is not a de Polignac number, because 21004104115 - 21 = 21004104113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21004104092 and 21004104101.

It is not an unprimeable number, because it can be changed into a prime (21004104113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2455516 + ... + 2464054.

It is an arithmetic number, because the mean of its divisors is an integer number (1584276750).

Almost surely, 221004104115 is an apocalyptic number.

21004104115 is a deficient number, since it is larger than the sum of its proper divisors (4344323885).

21004104115 is a wasteful number, since it uses less digits than its factorization.

21004104115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11286.

The product of its (nonzero) digits is 160, while the sum is 19.

Adding to 21004104115 its reverse (51140140012), we get a palindrome (72144244127).

The spelling of 21004104115 in words is "twenty-one billion, four million, one hundred four thousand, one hundred fifteen".

Divisors: 1 5 193 965 2549 8539 12745 42695 491957 1648027 2459785 8240135 21765911 108829555 4200820823 21004104115