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2101011342019 is a prime number
BaseRepresentation
bin11110100100101110000…
…010001110001011000011
321102212002002111200122121
4132210232002032023003
5233410332400421034
64245105152345111
7304536006513412
oct36445602161303
97385062450577
102101011342019
11740041147137
1229b234545197
13123180752635
1473991d71479
15399badd91b4
hex1e92e08e2c3

2101011342019 has 2 divisors, whose sum is σ = 2101011342020. Its totient is φ = 2101011342018.

The previous prime is 2101011341953. The next prime is 2101011342119. The reversal of 2101011342019 is 9102431101012.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2101011342019 - 223 = 2101002953411 is a prime.

It is a super-2 number, since 2×21010113420192 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2101011341984 and 2101011342002.

It is not a weakly prime, because it can be changed into another prime (2101011342119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050505671009 + 1050505671010.

It is an arithmetic number, because the mean of its divisors is an integer number (1050505671010).

Almost surely, 22101011342019 is an apocalyptic number.

2101011342019 is a deficient number, since it is larger than the sum of its proper divisors (1).

2101011342019 is an equidigital number, since it uses as much as digits as its factorization.

2101011342019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 25.

The spelling of 2101011342019 in words is "two trillion, one hundred one billion, eleven million, three hundred forty-two thousand, nineteen".