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210101330113 = 223942158431
BaseRepresentation
bin1100001110101100000…
…0111110000011000001
3202002022022201102101221
43003223000332003001
511420241420030423
6240304052355041
721115335561013
oct3035300760301
9662268642357
10210101330113
11811157a6004
1234876615a81
1316a73cc769c
14a2518a01b3
1556ea19ae5d
hex30eb03e0c1

210101330113 has 4 divisors (see below), whose sum is σ = 211043488768. Its totient is φ = 209159171460.

The previous prime is 210101330077. The next prime is 210101330119. The reversal of 210101330113 is 311033101012.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-210101330113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (210101330119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 471078993 + ... + 471079438.

It is an arithmetic number, because the mean of its divisors is an integer number (52760872192).

Almost surely, 2210101330113 is an apocalyptic number.

It is an amenable number.

210101330113 is a deficient number, since it is larger than the sum of its proper divisors (942158655).

210101330113 is an equidigital number, since it uses as much as digits as its factorization.

210101330113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 942158654.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 210101330113 its reverse (311033101012), we get a palindrome (521134431125).

The spelling of 210101330113 in words is "two hundred ten billion, one hundred one million, three hundred thirty thousand, one hundred thirteen".

Divisors: 1 223 942158431 210101330113