Base | Representation |
---|---|
bin | 11110100100110011111… |
… | …010111101100001110011 |
3 | 21102212022222100020001112 |
4 | 132210303322331201303 |
5 | 233411033141232011 |
6 | 4245123041223535 |
7 | 304541316122645 |
oct | 36446372754163 |
9 | 7385288306045 |
10 | 2101110102131 |
11 | 740091971067 |
12 | 29b261631bab |
13 | 123198050981 |
14 | 739a111c895 |
15 | 399c48e658b |
hex | 1e933ebd873 |
2101110102131 has 2 divisors, whose sum is σ = 2101110102132. Its totient is φ = 2101110102130.
The previous prime is 2101110102107. The next prime is 2101110102227. The reversal of 2101110102131 is 1312010111012.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2101110102131 - 218 = 2101109839987 is a prime.
It is a super-2 number, since 2×21011101021312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2101110102101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050555051065 + 1050555051066.
It is an arithmetic number, because the mean of its divisors is an integer number (1050555051066).
Almost surely, 22101110102131 is an apocalyptic number.
2101110102131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2101110102131 is an equidigital number, since it uses as much as digits as its factorization.
2101110102131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 2101110102131 its reverse (1312010111012), we get a palindrome (3413120213143).
The spelling of 2101110102131 in words is "two trillion, one hundred one billion, one hundred ten million, one hundred two thousand, one hundred thirty-one".
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